NetStumbler.org Forums - View Single Post

NetFox · 06-28-2004

Thanks, Thorn.

I have another question. From the data I got at distances from 2.5m to 50m, the average received data match the the log-distance path loss model perfectly with a path loss exponent of 1.44. However, the data was meassured outdoor, so I guess this path loss exponent might be too small.

Is it possible that the indications given by the card are just signal amplitude but power? So when calculating the power, I need to square the amplitude, in this way, the path loss exponent will become 2.88, which might make more sense.

06-28-2004	#3 (permalink)
NetFox Registered Member Join Date: Jun 2004 Posts: 6	Thanks, Thorn. I have another question. From the data I got at distances from 2.5m to 50m, the average received data match the the log-distance path loss model perfectly with a path loss exponent of 1.44. However, the data was meassured outdoor, so I guess this path loss exponent might be too small. Is it possible that the indications given by the card are just signal amplitude but power? So when calculating the power, I need to square the amplitude, in this way, the path loss exponent will become 2.88, which might make more sense. Last edited by NetFox : 06-28-2004 at 08:12 PM.